The velocity of electromagnetic radiation is the velocity of light (c), ie where, μo is the permeability and is the permittivity of free space.
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E°Cu2+/ cu = + 0.34 V and E°Ag+/Ag = + 0.80 V.Cu+2Ag+→ Cu2++2Ag(s)Applying the nernst equation E = E°-0.0592logCu2+Ag+2E° = E°cathode - E°anode = 0.80 - 0.34 = 0.46 VE = 0.46 - 0.0592log0.1301.0×10-4 = 0.46-0.0592×1.30×107 = 0.46 - 0.21 = 0.25 V.
(i) 2x(3x + 5xy) = 2x x 3x + 2x x 5xy = (2 x 3) X x X x + (2 x 5) X x X xy = 6x2 + 10x2y(ii) a2(2ab - 5c) = a2 x 2ab + a2 x (-5c) = (a x 2) x a2 x ab + [1 x (- 5)] x a2 x c = 2 x a2b + (- 5) x a2c = 2a3b - 5a2c
When brakes are applied, the frictional forces start acting on the drum of the wheel. If F is the force of friction and s is the distance travelled by truck or car, then work done against force of friction is at the cost of kinetic energy of vehicles.That is, work done i.e. ∴ Since kinetic energy and the retarding force on both the vehicles are same, therefore both will come to rest after travelling equal distances.
Let r be the base radius and h be the height.Then, volume of the cylinder i. e.,V1 = πr2hand volume of the cone i.e.,Hence, the required ratio is 3 : 1.
Since, tangents drawn from an exterior point to a circle are equal in length.
∴ AP = AS ...(i)BP = BQ ...(ii)CR = CQ ...(iii)and DR = DS ...(iv)Adding (i), (ii), (iii) and (iv), we getAP + BP + CR + DR = AS + BQ + CQ + DS⇒ (AP + BP) + (CR + DR)= (AS + DS) + (BQ + CQ)⇒ AB + CD = AD + BCHence, AB + CD = BC + DA.
∴ AP = AS ...(i)BP = BQ ...(ii)CR = CQ ...(iii)and DR = DS ...(iv)Adding (i), (ii), (iii) and (iv), we getAP + BP + CR + DR = AS + BQ + CQ + DS⇒ (AP + BP) + (CR + DR)= (AS + DS) + (BQ + CQ)⇒ AB + CD = AD + BCHence, AB + CD = BC + DA.
C.I.
xi
fi
fiixi
c.f
100-120
110
12
1320
12
120-140
130
14
1820
26
140-160
150
8
1200
34
160-180
170
6
1020
40
180-200
190
10
1900
50
Σfi = 50
Σfixi = 7260
(ii) Here the max. class frequency is 14, and the class corresponding to this frequency is 120-140. Model class is 120 - 140, Class size h = 20f1 = freq. of the model class = 14f0 = 12, f2 = 8 which lies in the class 120 - 140 l = 120. c.f. = 12, f = 14, h = 20Hence, mean = 145.2 mode = 125 median =
xi
fi
fiixi
c.f
100-120
110
12
1320
12
120-140
130
14
1820
26
140-160
150
8
1200
34
160-180
170
6
1020
40
180-200
190
10
1900
50
Σfi = 50
Σfixi = 7260
(ii) Here the max. class frequency is 14, and the class corresponding to this frequency is 120-140. Model class is 120 - 140, Class size h = 20f1 = freq. of the model class = 14f0 = 12, f2 = 8 which lies in the class 120 - 140 l = 120. c.f. = 12, f = 14, h = 20Hence, mean = 145.2 mode = 125 median =
Answer:(a) When sodium chloride is added to ferric hydroxide sol, the sol gets coagulated. This is because the Cl– ions from NaCl neutralize the +ve charge on Fe(OH)3 sol. Fe2O3.xH2O/Fe3+(b) Smoke coming out of the chimenys contain a lot of unburnt carbon particles smoke is the colloidal solution of the solid particles such as carbon arsenic dust particles etc.These particles are injurious to health and have to be precipitated since carbon particlesare charged particles and cannot be precipitated, thus metal plate of oppositely charged particles is used for their precipitation.This is do
gsebe Textbook Solutions Class 12 History. Free online History Textbook Questions and Answers. Students can find History 2018-19 syllabus, marking scheme, solved sample papers and previous year papers
The thermochemical equation is,From the above equation, it is clear that when 1 mol of H2O(l) is formed, 286 kJ of heat is released. The same amount of heat is absorbed by the surroundings.
Cross-aldol condensation: Aldol conden-sation of a mixture of two different aldehydes or ketones each containing an α-hydrogen gives a mixture of four products. Two products are made up of two molecules of same carbonyl compounds and are same as in case of simple aldol condensation. The other two products arise from the reaction between one molecule each of two different carbonyl compounds. These are called cross aldol conden-sation products and the reaction leading to formation of these products is known as cross-aldol conden-sation. Example:
Given, wavelength of the photon, = 275 nm
Energy of the photon is given by,
This corresponds to transition B as from the figure.
i) For maximum wavelength should be minimum. Minimum energy corresponds to transition A.
ii) For minimum wavelength, should be maximum. Maximum energy corresponds to transition D.
Energy of the photon is given by,
This corresponds to transition B as from the figure.
i) For maximum wavelength should be minimum. Minimum energy corresponds to transition A.
ii) For minimum wavelength, should be maximum. Maximum energy corresponds to transition D.
Since, the tangent at any point of a crcle is perpenedicular the radius throgh the point of contact.∴ ∠OAT = 90°and ∠OBT = 90°If two tangents are drawn to a circle from an external point, then they are equally inclined to the segment joining the centre to the point∴ ∠ATO = ∠BTOBut ∠ATO = 40°Now, ∠BTO = 40°In quadrilateral, ∠OBT, we have∠OAT + ∠OBT + ∠ATB + ∠AOB= 360°⇒ 90 + 90 + 80 + ∠AOB = 360°⇒ 260 + ∠AOB = 360°⇒ ∠AOB = 360° – 260° = 100°
Wavefront is defined as the locus of all the points in space that reach a particular distance by a propagating wave at the same instant.Huygen s principle:i) Each point of the wavefront is the source of a secondary disturbance and the wavelets emanating from these points spread out in all directions. These travel with the same velocity as that of the original wavefront.ii) The shape and position of the wave-front, after time t , is given by the tangential envelope to the secondary wavelets.A plane wavefront is incident on a thin convex lens:
(a) (i) ∆364-957744
(ii) The temple at Rampura = 954806
(b) Two features seen in the map which show that the region has seasonal rainfall:
(i) Seasonal rivers and streams
(ii) Broken ground.
(c) Distance in cm = 4.8 [Scale (2 cm = 1 km)]
Distance in km = 4.8/2 = 2.4 km.
(d) Chief form of irrigation is perennial lined well which is evidence as many blue dots can be seen in the map.
(e) Streams in 9478 do not join a river because these are disappearing streams, which dry up or disappear into the sand.
Another grid square is 9575.
(f) (i) Black broken line in 9575 represents disappeari
(ii) The temple at Rampura = 954806
(b) Two features seen in the map which show that the region has seasonal rainfall:
(i) Seasonal rivers and streams
(ii) Broken ground.
(c) Distance in cm = 4.8 [Scale (2 cm = 1 km)]
Distance in km = 4.8/2 = 2.4 km.
(d) Chief form of irrigation is perennial lined well which is evidence as many blue dots can be seen in the map.
(e) Streams in 9478 do not join a river because these are disappearing streams, which dry up or disappear into the sand.
Another grid square is 9575.
(f) (i) Black broken line in 9575 represents disappeari
Curdy white ppt. observed which is soluble in NH4OH
Escape velocity is minimum velocity with which a body must be thrown upward so that it may just escape.Expression for escape velocity:Let a body of mass m be escaped from gravitational field of the earth. During the course of motion, let at any instant body be at a distance r from the centre of the earth.The gravitational force between body and the earth is, and work done to raise the body by distance dr is, Total work done W in raising the body from the surface of the earth to infinity is,
કોઈ અણ દેશની વસ્તીનીતિના નિર્ધારણમાં જન્મદરના આંકડાઓ મહત્વ ધરાવે છે. જન્મદર એટલે દર હજારની વસ્તીએ વર્ષ દરમિયાન જન્મેલાં કુલ બાળકો દ્વારા વસ્તીમાં કેટલો વધારો થયો તે દર્શાવે છે. ભારતમાં જન્મદરનું પ્રમાણ નીચે દર્શાવેલ છે :ભારતમાં જન્મદરનું પ્રમાણ સતત ઘટતું ગયું છે. ભારત સરકારના કુટુંબનિયોજનના કાર્યક્રમોને લોકો દ્વારા સ્વીકૃતિ મળી. શહેરી વિસ્તારોની સરખામણીમાં ગ્રામીણ વિસ્તારોમાં જન્મદરનું પ્રમાણ ઉંચું જોવા મળે છે. તેનાં મુખ્ય કારણો નીચે પ્રમાણે છે :1. યોગ્ય આરોગ્યવિષયક સુવિધાઓનો અભાવ, 2. ગરીબી, 3. બેકારી, 4.નાની ઉંમરે લગ્ન કરવાનો રિવાજ વગેરે.
Business risk implies uncertainty of profits or danger of loss or continuity of business due to some unforeseen events.It refers to the chance of loss on account of unfavourable or unpredictable happenings.With every risk there is a possibility of loss which may or may not be measurable and the person or organization exposed to the risk may or may not be aware of the possibility of loss.Business enterprises constantly face two types of risk:
(i) Speculative
(i) Pure
Speculative risks involve both the possibility of gain as well as the possibility of loss. Pure risks involve only the possib
(i) Speculative
(i) Pure
Speculative risks involve both the possibility of gain as well as the possibility of loss. Pure risks involve only the possib
debentures represent

Loan capital of company